SOLUTION:

### Finding the Value of One Clock

Using the first equation: $9’oclock+9’oclock+3’oclock=21$ $9+9+3=21$ Therefore, 1 Clock = 3.

### Determining the Value of a Calculator

According to the second equation: $3calculators=30$ Thus, one calculator = 10.

The sum of numbers inside the calculator is: $1+2+3+4=10$ Therefore, the calculator’s value depends on the sum of the numbers inside it.

### Solving for the Bulb

According to the third equation: $1Bulb+1Bulb–1Bulb=15$ Canceling out the bulbs, we get: $1Bulbwithfivelights=15$ Therefore, one bulb with one light = 3.

For a bulb with four lights: $4×3=12$

### Final Equation

The final equation is: $9’oclock+Calculator(1+2+2+4)x3bulbs(withfourlightseach)$

Translating the final equation into numbers: $9+(1+2+2+4)x3(12)$ $9+9x36=9+324=333$

So, the answer is 333.

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